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8v^2-7v-9=0
a = 8; b = -7; c = -9;
Δ = b2-4ac
Δ = -72-4·8·(-9)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{337}}{2*8}=\frac{7-\sqrt{337}}{16} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{337}}{2*8}=\frac{7+\sqrt{337}}{16} $
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